# Line slope calculator x+5y=19

**Straight line given by points A[4; 3] and B[9; 2]**

## Calculation:

**Slope-intercept form of line:**y = -0.2x+3.8

**Canonical form of the line equation:**x+5y-19 = 0

**Parametric form of the line equation:**

x = 5t+4

y = -t+3 ; t ∈ R

**Slope:**m = -0.2

**Slope angle of line: φ =**-11°18'36″ = -0.1974 rad

**X intercept:**x

_{0}= 19

**Y intercept:**y

_{0}= q = 3.8

**Distance line from the origin:**d

_{0}= 3.7262

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; -1)

**Normal vector: n =**(1; 5)

**Midpoint of the segment AB: M =**[6.5; 2.5]

**Perpendicular Bisector equation:**5x-y-30 = 0

**Vector OA = (4; 3) ; |OA| = 5**

**Vector OB = (9; 2) ; |OB| = 9.2195**

**Scalar product OA .OB = 42**

**Angle ∠ AOB = 24°20'28″ = 0.4248 rad**